Question

evaluate: 2✓2 cos 45° cos 60° + 2✓3 cos 60° cot 30° - sin 90° sec 0°​

Answer 1

Answer:

Step-by-step explanation:

Given

2√2 cos 45° cos 60° + 2√3 cos 60° cot 30° - sin 90° sec 0°

= 2√2 × 1/√2 × 1/2 + 2√3 × 1/2 × 1/√3 - 1 × 1

= √2 and √2 are cancelled

= (2 × 1 × 1/2 )+ ( 2 ×1 ×1/ √3 × 2× √3) - 1

= 2 and 2 are cancelled

= ( 1 × 1 × 1 ) + (2 / √3^2 × 2) -1

= 1 + numerator 2 and denominator 2 are cancelled then 3 - 1

= 1 + 3 - 1

= 3 is the answer