Math, asked by nithika45, 1 year ago

evaluate (-2_3)^0+(-2_3)×(-2_3)^0-(-2_3)^0

Answers

Answered by suryakirancm
5

Answer:

123234454km

Step-by-step explanation:


Answered by rajeev378
21
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Here is your answer

( \frac{ - 2}{3} ) {}^{0}  + ( \frac{ - 2}{3} ) \times ( \frac{ - 2}{3} ) {}^{0}  - ( \frac{ - 2}{3} ) {}^{0}  \\  \\  = 1 + ( \frac{ - 2}{3} ) \times 1 - 1 \\  \\  =  \frac{ - 2}{3}

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