Question

EVALUATE: 2^40+2^39+2^38/2^41+2^40+2^39
Hello, could someone explain the first step in the image to me? How do we get [2^2+2^1+2^0] ? I'll mark as Brainliest!

Answer 1

Answer:

240+239+238

= \dfrac{2^{38}[2^{2}+2^{1}+2^{0}]}{2^{39}[2^2 +2^{1}-2^{0}]}=239[22+21−20]238[22+21+20]

= \dfrac{2^{38}[4+2 +1 ] }{2^{39}[4 +2 - 1]}=239[4+2−1]238[4+2+1]

= \dfrac{1[7] }{2[5]}=2[5]1[7]

= \dfrac{7}{10}=107