Question

Evaluate : 2 cosec^2 30° + 3 sin^2 60° - 3/4 tan^2 30°​

Answer 1

Here is ur answer....

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$2 { \cosec}^{2} 30 + 3 {sin}^{2} 60 - \frac{3}{4} {tan}^{2} 30 \\ = 2 {(2)}^{2} + 3 {( \frac{ \sqrt{3} }{2} )}^{2} - \frac{3}{4} {( \frac{1}{ \sqrt{3} } )}^{2} \\ = 2(4) + 3( \frac{3}{4} ) - \frac{3}{4} ( \frac{1}{3} ) \\ = 8 + \frac{9}{4} - \frac{1}{4} \\ = \frac{32 + 9 - 1}{4} \\ = \frac{40}{4} \\ = 10$

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