Math, asked by goswamikhushi1829, 5 months ago

Evaluate 2 cot^2 30° + cos^2 30° - sin^2 60° ​

Answers

Answered by Anonymous
8

Now,

cot 30° – 2 cos 60°

= (V3)2 – 2 x

3 =

1 2

= 32

= 1

3

4

please mark me as BRAINLIEST and like

Answered by muzamuzu405
0

Answer:

Hey mate the answer is 3/2

2 cot^2 30° + cos^2 30° - sin^2 60° =

2 x (

2 \times  ( \sqrt{3 }  \div 2 ) {}^{2}  + ( \sqrt{3}  \div 2) {}^{2}  -  (\sqrt{3}  \div 2) {}^{2}

 =  \: 2 \times 3 \div 4 + 3 \div 4 - 3 \div 4

 = 3 \div 2 + 3 \div 4 - 3 \div 4

 = 3 \div 2

= 3/2

Hope this will help you

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