Math, asked by mariasania74, 3 months ago

Evaluate :
2" x6m+1 X10M-n x15m+n-2
4m x32m+n x25m-1​

Answers

Answered by anshagarwalcls7b
0

Answer:

Evaluate : 2^N Xx 6^(M + 1 ) Xx 10^( M - N ) Xx 15^(M + N - 2)/4^M Xx 3^(2m + N) Xx 25^(M - 1 )

Similar questions