Evaluate 211×189 using suitable identity
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a square + b square by using identity
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211×189
=> (200+11)×(200-11)
using (a+b)(a-b) = a²-b²
=> we have , (200+11)(200-11) = (200)²-(11)1
=> 40000-121 = 39879
hope this helps
=> (200+11)×(200-11)
using (a+b)(a-b) = a²-b²
=> we have , (200+11)(200-11) = (200)²-(11)1
=> 40000-121 = 39879
hope this helps
Shrishti20:
Thanks
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