Math, asked by bk7112667, 1 month ago

evaluate : (2a + 3b + 4c) power 2 + (2a - 3b + 4c) power 2 + (2a + 3b - 4c) power 2​

Answers

Answered by xXCuteBoyXx01
85

AnswerWe know,

(x+y+z)2=x2+y2+z2+2xy+2yz+2zx        [Identity]

Here, 

x=2a

y=3b

z=4c

Putting Values in Identity, We get :

⇒ (2a+3b+4c)2=(2a)2+(3b)2+(4c)2+2(2a)(3b)+2(3b)(4c)+2(4c)(2a)

                                  =4a2+9b2+16c2+12ab+24bc+16ca

Step-by-step explanation:

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Answered by lava2007
0

Answer:

(x+y+z)

2

=x

2

+y

2

+z

2

+2xy+2yz+2zx [Identity]

Here,

x=2a

y=3b

z=4c

Putting Values in Identity, We get :

⇒ (2a+3b+4c)

2

=(2a)

2

+(3b)

2

+(4c)

2

+2(2a)(3b)+2(3b)(4c)+2(4c)(2a)

=4a

2

+9b

2

+16c

2

+12ab+24bc+16ca

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