evaluate : (2a + 3b + 4c) power 2 + (2a - 3b + 4c) power 2 + (2a + 3b - 4c) power 2
Answers
Answered by
85
AnswerWe know,
(x+y+z)2=x2+y2+z2+2xy+2yz+2zx [Identity]
Here,
x=2a
y=3b
z=4c
Putting Values in Identity, We get :
⇒ (2a+3b+4c)2=(2a)2+(3b)2+(4c)2+2(2a)(3b)+2(3b)(4c)+2(4c)(2a)
=4a2+9b2+16c2+12ab+24bc+16ca
Step-by-step explanation:
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Answered by
0
Answer:
(x+y+z)
2
=x
2
+y
2
+z
2
+2xy+2yz+2zx [Identity]
Here,
x=2a
y=3b
z=4c
Putting Values in Identity, We get :
⇒ (2a+3b+4c)
2
=(2a)
2
+(3b)
2
+(4c)
2
+2(2a)(3b)+2(3b)(4c)+2(4c)(2a)
=4a
2
+9b
2
+16c
2
+12ab+24bc+16ca
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