Question

Evaluate
2sin680
cos220
2cot150
5tan750
tan20°tan40'tan 50°tan700​

Answer 1

Step-by-step explanation:

The Formulas to be used in this Questions are:=>cos(90 - x) = sin x   e.g. cos 220 = cos(90-68)= sin 220

=>tan(90 - x) = cot x    e.g. cot 15 = cot(90-75) = tan 150

=>tanx.cotx = 1

Now Question is,

2sin680/cos220 - 2cot150/5tan750 - (3/5)tan450 tan20 tan40 tan50 tan70

=2sin68/sin68 - 2tan75/5tan75 - (3/5)1 tan20 tan40 cot40 cot 20

=2 - 2/5 - 3/5= 1

This is the Answer