Question

Evaluate :-

2tan 260+4 sin260−2 tan230.sec 2 30/
2sin245−5 sin90+3 cos290−cos 60

Answer 1

Given: The expression 2tan^2 60 + 4sin^2 60 - 2tan^2 30 . sec^2 30 /

2sin^2 45 - 5sin90 + 3cos^2 90 - cos 60

To find: The value of the given expression.

Solution:

• Now we have given:

                    2tan^2 60 +4sin^2 60 -2tan^2 30.sec^2 30 /  2sin^2 45 - 5sin90 +3cos^2 90 - cos 60

• Now putting the values in it, we get:

                    2(√3)² + 4(√3/2)² - 2(1/√3)².(2/√3)² / 2(1/√2)² - 5(1) + 3(0) - 1/2

                    6 + 3 - 4/9 / 1 - 5 - 1/2

                    9 - 4/9 / - 4 - 1/2

                    77/9 / -9/2

                    -77 x 2 / 81

                    -154/81

Answer:

              So the value of the given expression is -154/81