Question

evaluate (2x-1/x) whole square

urgent ​

Answer 1

Answer:

$(2x - \frac{1}{x} )^{2} \\ \\ \\ = > 4 {x}^{2} + { (\frac{1}{x} )}^{2} - 2 \times 2x \times \frac{1}{x} \\ \\ = > 4 {x}^{2} + \frac{1}{ {x}^{2} } - 4$

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