Math, asked by sfaditya155, 1 year ago

Evaluate--(2x+5y)(2x+3y)

Answers

Answered by frozen2
1
2x2 + ( 5y + 3y )2x + 5y×3y
4x2 + ( 8y )2x + 15y2
4x2 + 16xy + 15y2

frozen2: mark it brainlist
Answered by ABHINAVrAI
2



Simplifying (2x + 3y)(2x + -5y) = 0
  Multiply (2x + 3y) * (2x + -5y) (2x * (2x + -5y) + 3y * (2x + -5y)) = 0
((2x * 2x + -5y * 2x) + 3y * (2x + -5y)) = 0
 Reorder the terms: ((-10xy + 4x2) + 3y * (2x + -5y)) = 0
((-10xy + 4x2) + 3y * (2x + -5y)) = 0
(-10xy + 4x2 + (2x * 3y + -5y * 3y)) = 0
(-10xy + 4x2 + (6xy + -15y2)) = 0
 Reorder the terms: (-10xy + 6xy + 4x2 + -15y2) = 0
 Combine like terms: -10xy + 6xy = -4xy (-4xy + 4x2 + -15y2) = 0
 Solving -4xy + 4x2 + -15y2 = 0
 Solving for variable 'x'.
 Factor a trinomial.
(2x + -5y)(2x + 3y) = 0
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