Evaluate: (3^-1+3^-2)/3^0+3
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Answer:
(3^-1+3^-2)/3^0+3
by using a^-m=1/a^+m
(1/3+1/3^2)/3^0+3
in denominator by using a^m+n=a^mxa^n
(1/3+1/9)/3^0x3^3
on taking LCM in numenator
(3+1/9)/1 x 27
4/9 x27/1
4x3
12
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