Math, asked by BRAINLIESTY, 10 months ago

Evaluate: (3^-1+3^-2)/3^0+3

Answers

Answered by Shubh2516
1

Answer:

(3^-1+3^-2)/3^0+3

by using a^-m=1/a^+m

(1/3+1/3^2)/3^0+3

in denominator by using a^m+n=a^mxa^n

(1/3+1/9)/3^0x3^3

on taking LCM in numenator

(3+1/9)/1 x 27

4/9 x27/1

4x3

12

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