Question

evaluate (3^-1+6^-1)^0 + (2^-1 -3^-1)^-1​

Answer 1

Step-by-step explanation:

(3^-1+6^-1)^0 + (2^-1-3^-1)^-1

= 1 + (1/2-1/3)^-1 [m ^0 = 1 ]

= 1 + ( 2 - 3 ) [(m/n )^-1 = (n / m)^1 ]

= 1+(-1)

= 1-1

= 0

Answer 2

Answer:

7 Ans.

Step-by-step explanation:

Hope it's help you.