Question

Evaluate :
{✓3 +2✓2}
&
{√5-2√6}​

Answer 1

Answer:

Hi,

1) v( 5-2v6)

= V[ (V3 )? + ( v2)? 2 x v3 x v2]

= v ( V3 - v2)? =

= V3 - v2 ---(1)

2) V[ 10 2v21 ]

= V[ ( V7)? + ( v3 )? - 2 x v7 x v3]

= v ( v7 - V3 )? =

= 17 - V3 ---( 2)

Now,

V(5 - 2v6) + ( 10 - 2v21)

= (1) + (2)

= V3 - V2 + V7 - V3

V7 - v2

Step-by-step explanation:

plz follow

Answer 2

Answer:

Find the real values of x which satisfy the equation (5+26–√)x2−3+(5−26–√)x2−3=10

My Attempt

e10=e(5+26√)x2−3+(5−26√)x2−3=e(5+26√)x2−3⋅e(5−26√)x2−3=[e(5+26√)⋅e(5−26√)]x2−3=[e10]x2−3=e10(x2−3)⟹x2−3=1⟹x=±2