evaluate 3*3matrix
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Open the matrix using the first row to find the determinant
1*[(1+a)(1+b)-1] - 1*[1*(1+b)- 1] + 1*[1-(1+a)]
= a + b - b + (-a)
= 0
1*[(1+a)(1+b)-1] - 1*[1*(1+b)- 1] + 1*[1-(1+a)]
= a + b - b + (-a)
= 0
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