evaluate 3 cos 55/7 sin 35-3root ( tan10 tan 30 tan40 tan50 tan80)
Answers
Answered by
4
Answer:
GIVEN
3cos55 / 7sin35 - 4/7(cos 70 cosec 20 ) / (tan5 tan25 tan45 tan65 tan85 )
USE
tan x = cot (90-x)
cot x = tan (90-x)
sin x = cos (90-x)
cos x = sin (90-x)
= [3 (cos55 / 7cos55)] - 4[(cos70 / sin20)] / 7 [tan5 tan25 tan45 tan65 tan85]
= (3 / 7) - 4 / 7(tan5 cot5 tan25 cot25 tan45)
= 3/7 - 4/7
= - 1 / 7
sonabrainly:
mark it the brinaliest
Answered by
0
Answer:
-4/7
Step-by-step explanation:
3cos55/7sin35=3/7
√3(tan 10. tan80. tan 40. tan50.1/√3)=√3×1×1×1/√3
=√3/√3=1
3/7-1=-4/7
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