Math, asked by avni6279, 1 year ago

evaluate 3 cot^2 60 + sec^245​

Answers

Answered by Anonymous
5

Answer:

First of all, values of cot 60° and sec 45° :

\tt{cot \:60° = \frac{1}{\sqrt{3}} \: and\: sec\: 45° = \sqrt{2}}\\

3 cot^2 (60°) + sec^2 (45°) = \tt{3 \times \frac{1}{3} + \sqrt{2}^{2}}\\

=》 3

Answered by Anonymous
1

Answer:

Step-by-step explanation:

3 cot² 60° + sec²45​°

=3(1/√3)² +(√2)²

=3*1/3+2

=1+2

=3

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