Math, asked by Dharmendras3911, 10 months ago

Evaluate 3+jk+k^33+jk+k 3
3, plus, j, k, plus, k, cubed when j=2j=2j, equals, 2 and k=6k=6k, equals, 6.

Answers

Answered by amitnrw
27

3 + jk  + k³ = 231  when j = 2 & k = 6

Step-by-step explanation:

We need to Evaluate

3 + jk  + k³

given

j = 2

k = 6

Just putting the value of j & k

in 3 + jk  + k³

= 3 + (2)(6)  + 6³

= 3 + 12 + 216

= 231

3 + jk  + k³ = 231

Answered by BastianCo22
1

Answer:

231

Step-by-step explanation:

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