Evaluate :
3 sin 3A + 2 cos (2A + 5°)
2 cos 3A - sin (2A - 10°)
when A = 20°
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Answer:
ANSWER (1)
ANSWER (2)
Step-by-step explanation:
QUEATION (1)
3 sin3A + 2 cos(2A+5°)
=3 sin(3 x 20) + 2 cos(2 x 20 + 5)
=3 sin(60) + 2 cos(45)
=3 x √3/2 + 1/√2
=(3√5 + 2)/√2
QUESTION (2)
2 cos3A - sin(2A - 10)
= 2 cos(3 x 20) - sin(2 x 20 - 10)
= 2 cos60 - sin30
= 2 x √3/2 - 1/2
= √3 - 1/2
= (2√3-1)/2
HOPE IT HELPED
d=(´▽`)=b
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