evaluate 3cotsquare60+secsquare45
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Let first find the values for cot square 60and sec square 45.
cot ^2 60=(1/√3)^2
=1/3
sec^2 45=(√2)^2
=2
3[cot^2 60] + sec^2 45 =3(1/3)+2 =1+2=3
Therefore the value for this expression is 3.
Hope that it would have been helpful to you. Please mark my answer a the brainliest.
cot ^2 60=(1/√3)^2
=1/3
sec^2 45=(√2)^2
=2
3[cot^2 60] + sec^2 45 =3(1/3)+2 =1+2=3
Therefore the value for this expression is 3.
Hope that it would have been helpful to you. Please mark my answer a the brainliest.
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