Question

evaluate 3sin²45°+2cos²30°-cot²30°​

Answer 1

Ans = 0

Step-by-step explanation:

3×(1/root 2)^2 + 2×( root 3/2)^2 - (root 3 )^2 [ Value of sin45° , cos 30° , cot 30°]

= 3× 1/2 + 2×3/4 - 3

= 3/2 + 3/2 - 3

3+ 3 - 6

= -----------------

2

6 - 6

= ----------

2

= 0/2

= 0 (ans)

Answer 2

Step-by-step explanation:

3sin²45°+2cos²30°-cot²30°

cos (90° - θ) = sin θ

cot (90° - θ) = tan θ

= 3 sin^2 45 + 2 cos ^2 (90 -30) - cot ^2 (90-60)

= 3 * (1/√2)^2 + 2 (√3/2)^2 - (√3)^2

= 3* 1/ 2 + 2 * 3/4- 3

= 3 /2 + 3/2 - 3

= 6/2 - 3

= 3 - 3

=0