Question

Evaluate (41)^2 with the identity (a+b)^2=a^2+2ab+b^2

Answer 1

Answer:

The answer is 1681

Step-by-step explanation:

(a+b)^2=a^2+2ab+b^2

Now take a = 40, b = 1

So

From above

(40+1)^2 = (40)^2 + 2×40× 1 = 1^2

41^2 = 1600 + 80 +1 = 1681

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Answer 2

Answer:(41)²

So according to the identity we can write (41)² as (40+1)²

Therefore, according to the question↓

(a+b)²=a²+2ab+b²

(40+1)²=1600+2×40×1+1

1600+80+1

1681

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