Question

Evaluate: −
(

/
) − −

(
−
/+
).​

Answer 1

Answer:

Hope it helps

Answer 2

Good afternoon answer is below

Step-by-step explanation:

identify:-

${ \tan }^{ - 1} \frac{x}{y} - { \tan }^{ - 1} \frac{x - y}{x + y} = { \tan }^{ - 1} \frac{ \frac{x}{y} - \frac{x - y}{x + y} }{ 1 + \frac{x}{y} (\frac{x - y}{x + y}) }$

$\rightrightarrows \: { \tan }^{ - 1} \frac{ {x}^{2} + xy - xy + {y}^{2} }{{y}^{2} + xy - xy + {x}^{2}}$

$\rightrightarrows \: { \tan}^{ - 1} \frac{1}{1}$

$\rightrightarrows \: ( { \tan }^{ - 1} 1) = \frac{\pi}{4}$

Additional information

• the formula can only be applied if xy>-1
• in this case xy is always greater than -1