Evaluate √(5-2√6)+√(10-2√21)
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Answered by
20
Hi ,
1 ) √( 5-2√6 )
= √[ (√3 )² + ( √2 )² - 2 × √3 × √2 ]
= √ ( √3 - √2 )²
= √3 - √2 ---( 1 )
2 ) √[ 10 - 2√21 ]
= √[ ( √7 )² + ( √3 )² - 2 × √7 × √3 ]
= √ ( √7 - √3 )²
= √7 - √3 ---( 2 )
Now ,
√( 5 - 2√6 ) + √( 10 - 2√21 )
= ( 1 ) + ( 2 )
= √3 - √2 + √7 - √3
= √7 - √2
I hope this helps you.
: )
1 ) √( 5-2√6 )
= √[ (√3 )² + ( √2 )² - 2 × √3 × √2 ]
= √ ( √3 - √2 )²
= √3 - √2 ---( 1 )
2 ) √[ 10 - 2√21 ]
= √[ ( √7 )² + ( √3 )² - 2 × √7 × √3 ]
= √ ( √7 - √3 )²
= √7 - √3 ---( 2 )
Now ,
√( 5 - 2√6 ) + √( 10 - 2√21 )
= ( 1 ) + ( 2 )
= √3 - √2 + √7 - √3
= √7 - √2
I hope this helps you.
: )
thanks sir
Answered by
8
Answer:
√(5-2√6)+√(10-2√21)
THEN SOLVE (1)
(1)√(5-2√6)
√[(√3)²+(√2)²-2×√3×√2]
√[√3-√2]
√3-√2 ....... (1)
(2) √[10-2√21]
√[(7)²+(√3)-2×√7×√3]
√[(√7-√3)²]
√(√7-√3)²
√7-√3 ...........(2)
THEN ADD BOTH (1) + (2)
√(√(5-2√6)+√(10-2√21)
(1) + (2)
√3-√2+√7-√3
=√7-√2 is ans
ANSWER IS √7-√2
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