Question

evaluate (_(5+m))²_4(m_2)(16) = 0​

Answer 1

hi mate,

solution:y

(-(5+m))²-4(m-2)(16) = 0

25 + m² +( - 4m + 8 ) 16 = 0

25 + m² - 64 m +128 = 0

m² - 64 m + 128 + 25 = 0

m² - 64 m + 153 = 0

Solving m²-64m+153 = 0 by the Quadratic Formula

- B ± √ B²-4AC

m = ————————

2A

In our case, A = 1

B = -64

C = 153

Accordingly, B² - 4AC =

4096 - 612 =

3484

Applying the quadratic formula :

64 ± √ 3484

m = ——————

2

√ 3484 = √ 2•2•13•67 =

± 2 • √ 871

√ 871 , rounded to 4 decimal digits, is 29.5127

So now we are looking at:

m = ( 64 ± 2 • 29.513 ) / 2

Two real solutions:

m =(64+√3484)/2=32+√ 871 = 61.513

or:

m =(64-√3484)/2=32-√ 871 = 2.487

Two solutions were found :

m =(64-√3484)/2=32-√ 871 = 2.487

m =(64+√3484)/2=32+√ 871 = 61.513

i hope it helps you.