Question

Evaluate 501 502 503 xyz dx dy dz​

Answer 1

Answer:

We know 501×501 =(500+1)(500+1)

=(500+1) 2

We know suitable identity is (x+y) 2

=x 2+2xy+y 2

Therefore, the value of (500+1) 2 is

=(500) 2+2(500)(1)+(1) 2

=250000+1000+1

=251001