Math, asked by ayushkumar2391, 1 year ago

evaluate 6/root12-root3​

Answers

Answered by kumarisakshi211
3

Answer:


Step-by-step explanation:

6/√12-√3

=6/2√3-√3 (√12=2√3)

=(6-6)/2√3 (by finding LCM)

=0


toptisha: it's not zero
Answered by toptisha
8
6/√12-√3
6/√2*√2*√3-√3
6/2√3-√3
6/√3
2*√3*√3/√3
2*√3
So the final answer is2√3 Friend

toptisha: brainliest plssss
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