Question

Evaluate..................................................

Answer 1

Answer is 1/3


It is a maths question

Answer 2

Explanation:

using relations,

sec(90-A)=cosecA

tan(90-A)=cotA

sin(90-A)= cosA

identities

sin²A + cos²= 1

sec²A= 1 + tan²A

cosec²A=1 + cot²A

→ (cosec²A - cot²A)/2(sin²25 + cos²25) + (2tan²30 tan²32 .cot²32/3(sec²33 -tan²33))

→1/2 +(2(1/3)/3))

→1/2 + 2/9

→13/18