Math, asked by haldersumit21, 1 year ago

Evaluate (90)3+(15)3+(-105)^3 using identies

Answers

Answered by Elaratitan
0

a³+b³+c³=3abc

when,

a+b+c= 0

90+15-105= 0

so,

3×90×15×105=425,250<<<<answer

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