evaluate (99)3 using identity
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(a + b)3 = a3 + b3 + 3ab(a + b) and (a- b)3 = a3 - b3 -3ab(a - b) (99)3 = (100 − 1)3 = (100)3 − (1)3 − 3(100) (1) (100 − 1) = 1000000 − 1 − 300(99) = 1000000 − 1 − 29700 = 970299
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