Question

two particles are simultaneously projected in opposite direction horizontally from a given point in space where gravity ji is uniform if U1 and U2 be the initial speed then the time after which there velocities are mutually perpendicular is given by

Answer 1

Answer:

The time will be √u1u2/(ji)

Explanation:

According to the problem it is given that the velocities of  two particles are perpendicular to each other.

let the velocities are v1 and v2 respectively.

Therefore the dot product of the two velocities will be,

v1 .v2 = 0

Now we know velocity = u - gt

here g = ji

therefore,

(u1i−(ji)tj) . (- u2i−(ji)tj) = 0

=> (ji)^2 x t^2 = u1 x u2

=> t = √u1u2/(ji)