evaluate [998]^3 by using identity
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Answered by
45
998=1000-2
998³=(1000-2)³,which is in the form of (a-b) ³
(a-b) ³=a³-b³-3ab(a-b)
that implies, 1000³-2³-3*1000*2(1000-2)
=1000000000-8-6000(998)
=1000000000-5988000-8
=994011992
therefore, 998³=994011992
998³=(1000-2)³,which is in the form of (a-b) ³
(a-b) ³=a³-b³-3ab(a-b)
that implies, 1000³-2³-3*1000*2(1000-2)
=1000000000-8-6000(998)
=1000000000-5988000-8
=994011992
therefore, 998³=994011992
Answered by
0
Answer:
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Step-by-step explanation:
998=1000-2
998³=(1000-2)³,which is in the form of (a-b) ³
(a-b) ³=a³-b³-3ab(a-b)
that implies, 1000³-2³-3*1000*2(1000-2)
=1000000000-8-6000(998)
=1000000000-5988000-8
=994011992
therefore, 998³=994011992
Hope it help you.
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