Math, asked by nithish1114, 5 months ago

Evaluate (999)^3. Find this answer​

Answers

Answered by Seafairy
33

\large\mathtt{997,002,999}

Method :

Solved using binomial theorem.

Given :

{(999)}^3

Solution :

\implies {(999)}^{3}

\implies {(1000-1)}^{3}

 \text{General Form of binomial equation :}

\color{purple}{{(x-a)}^{3}=3C_0{x}^{3}-3C_1{x}^2a+3C_2x{a}^2-3C_3a^3}

x=1000,a=1

\mathtt{\implies 3C_0(1000)^3-3C_1(1000)^2(1)+3C_2(1000)(1)^2-3C_3(1)^3}

\mathtt{\implies(1000000000)-3(1000000)+\frac{3\times2}{1\times2}(1000)-1}

\mathtt{\implies 1000000000-3(1000000)+3(1000)-1}

\mathtt{\implies 1000000000-3000000+3000-1}

\mathtt{\implies 997,002,999}

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