evaluate (a+1)(a-1)(a2+1) and (a-1) (a2+a+1)
pls answer fast...
Answers
Answered by
0
Answer:
a=0
Step-by-step explanation:
(a+1)(a-1)(a²+1) = (a-1)(a²+a+1)
(a+1)(a²+1) = a²+a+1
a³+a+a²+1 = a²+a+1
a³ = 0
a = 0.
Answered by
0
Answer:
a=0
Step-by-step explanation:
a+1)(a-1) (a2+1)=(a-1) (a2+a+1)
a2-1) (a2+1)=(a3-1)
a4-1) =a3-1
a=0
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