Question

Evaluate

A.√3-2√2
B.√(√2-1)/(√2+1)
C.√5+2√6
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Answer 1

Answer:

$a) \sqrt{2} \\ b ) \sqrt{2 } - 1 \\ c)$

Step-by-step explanation:

$a) \sqrt{3 - 2} \sqrt{2 } \\ \\ calculate \: the \: \\ product \: of \: the \: root = > \\ \\ \sqrt{6 - 4} \\ subtract \: \: 4 \: \: from \: \: 6 = > \\ \\ \sqrt{2}$

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$\sqrt{( \sqrt{2 - 1)} } \div ( \sqrt{2} + 1) \\ subtract \: \: 1 \: \: from \: \: 2 \\ to \: get \: 1 = > \\ \\ \\ \frac{ \sqrt{ \sqrt{1} } }{ \sqrt{2 } + 1} \\ calculate \ : \: the \: \: square \: \: root \: of \: 1 \\ and \: get \: 1 = > \\ \\ \\ \frac{ \sqrt{1} }{ \sqrt{2} + 1} \\ calculate \: \: the \: \: square \: \: root \: \: o f\: \: \: 1 \\ and \: get \: \: 1 = > \\ \\ \frac{1}{ \sqrt{2} + 1} \\ \\ = > \frac{ \sqrt{2} - 1}{( \sqrt{2} + 1)( \sqrt{2 - 1)} } \\ \\ = > \frac{ \sqrt{2} - 1 }{( \sqrt{2) {}^{2} } - 1 {}^{2} } \\ \\ = > \frac{ \sqrt{2} - 1}{2 - 1} \\ \\ = > \frac{ \sqrt{2 } - 1}{2} \\ \\ = > \sqrt{2} - 1$