evaluate a+b-c+d for a = 1,b =2, c = 3,d =4
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Step-by-step explanation:
Given
ba=31⇒a=3b
cb=2⇒c=2b
dc=21⇒d=2c⇒d=2×2b=b
ed=3⇒e=3d⇒e=3b
fe=41⇒f=4e⇒f=34b
∴defabc=b×3b×34b3b
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Answer:
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hope it helps you
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