Question

Evaluate alpha and beta in the epn E= k. M^alpha .c^beta where E is kinetic energy, m is mass, c is velocity and k is dimensional constant

Answer 1

Let Alpha be 'a' and Beta be 'b'

Answer:

E=1/2mv^2_________1

from question..

E=1/2m^ac^b_______2

dimensions of _1

[ML^2T^-2]

dimensions of _2

[M^aL^bT^-b]

equating powers M

1=a

equating powers of L

2=b

thus a=1

b=2