Math, asked by neginidhi58gmailcom, 1 year ago

Evaluate by laws of exponent (3^5/3^8)^5/3^-5

Answers

Answered by Singh1111111
0

(-2/7)-4 × (-5/7)2

= (7/-2)4 × (-5/7)2

= (-7/2)4 × (-5/7)2 [Since, (7/-2) = (-7/2)]

= (-7)4/24 × (-5)2/72 

= {74 × (-5)2}/{24 × 72 } [Since, (-7)4 = 74]

= {72 × (-5)2 }/24 

= [49 × (-5) × (-5)]/16 

= 1225/16
Answered by lavanya35
0
(3^5÷3^8)^5 ÷ 3^-5
(3^3)^5÷3^-5
3^15÷3^-5
3^20
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