Question

evaluate [cos^-1(-√3/2) +π/6]

Answer 1

Answer:

cos [cos–1(-√3/2) + π/6]

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Step-by-step explanation:

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Answer 2

Question (with correction):

Evaluate

$\cos \left[ { \cos }^{ - 1} \left( \frac{ - \sqrt{3} }{2} \right) + \frac{\pi}{6} \right]$

Solution:

$\cos \left[ { \cos }^{ - 1} \left( \frac{ - \sqrt{3} }{2} \right) + \frac{\pi}{6} \right] \\ \\ \cos \left[ { \cos }^{ - 1} \left( \cos \frac{ 5\pi }{6}\right) + \frac{\pi}{6} \right] \\ \\ \left ( \because \: \cos \frac{5\pi}{6} = \frac{ - \sqrt{3} }{2} \right ) \\ \\ = > \cos \left( \frac{5\pi}{6} + \frac{\pi}{6} \right) \\ \\ \left ( \because \: \cos {}^{ - 1} \cos \: x = x; \texttt{ x} \: \epsilon \: [ 0,\pi] \right) \\ \\ \implies \: \: \boxed{\cos(\pi) = - 1}$

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