Math, asked by syedmaroof18, 5 months ago

evaluate cos^2theta tan^2theta + tan^2theta sin^2 theta in terms of tan theta​

Answers

Answered by amitnrw
3

Given :  Cos²θtan²θ + tan²θsin²θ

To Find : Evaluate in terms of tan theta. ​

Solution

Cos²θtan²θ + tan²θsin²θ

Taking tan²θ common

= tan²θ (Cos²θ + sin²θ )

Apply the formula that Cos²θ + sin²θ   = 1

= tan²θ (1 )

= tan²θ

Cos²θtan²θ + tan²θsin²θ  = tan²θ  

Learn More:

https://brainly.in/question/23736455

If acos3θ+3acosθsin²θ=m, asin3θ+2acos²θsinθ=n, prove that (m+n ...

https://brainly.in/question/15923131

If cos² theta = 0 then simplify.HELP.URGENT!!! no spam, Question n ...

https://brainly.in/question/10065050

Similar questions