Math, asked by tl12, 6 months ago

Evaluate: cos 48°-sin 42°

Answers

Answered by bsuresh2233

0

Answer:

Value \:of \: cos48\degree-sin42\degreeValueofcos48°−sin42°

=cos48\degree-sin(90-48\degree)=cos48°−sin(90−48°)

=cos48\degree-cos48\degree=cos48°−cos48°

/* We know that,

Sin(90°-A)=cosA */

=0=0

Therefore,

Value \:of \: cos48\degree-sin42\degree=0Valueofcos48°−sin42°=0

•••♪

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