Question

evaluate cos 48°-sin42°​

Answer 1

Answer:

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To find Cos 48° – Sin 42°

We know that Cos (90 – θ) = Sin θ……..(1)

So we can write Cos 48° as

Cos 48° = Cos (90 – 42)

Cos 48° = Cos (90 – 42) = Sin 42°………(2)

Cos 48° – Sin 42°

From equation (2) we can write the above equation as

Sin 42°– Sin 42°

= 0

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Answer 2

To Evaluate :

• Cos 48 degree - Sin 42 degree.

Answer :

• 0

To find :

• Cos 48o – Sin 42o

We know that :

• Cos (90 – θ) = Sin θ……..(1)

So we can write Cos 48° as :

• Cos 48° = Cos (90 – 42)

• Cos 48° = Cos (90 – 42) = Sin 42°………(2)

• Cos 48° – Sin 42°

From equation (2) we can write the above equation as :

• Sin 42° – Sin 42°.
• 0.