Evaluate cos 75degree + cos 15 degree
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cos75° + cos15°
= cos (45° + 30°) + cos (45°-30°)
NOTE:-
- cos(A+B)=cosA.cosB -sinA.sinB
- cos (A-B)=cosA.cosB +sinA.sinB
now, coming to the Question
=(cos45°. cos 30° - sin 45° + sin 30°) +
( cos 45°.cos30°+ sin45°+sin30°)
= 2cos45°.cos30°
=2.(1/√2).(√3/2)
=√6/2
Hope it helps!! ☺️
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