Math, asked by jainmayank81, 10 months ago

the present ages of an arnav parents are in ratio 4 is to 5 .. 8 years later the ratio of the ages change to 5 is 6 find the present ages​

Answers

Answered by deepsen640
47

Answer:

Present Age of his father = 40 years

Present Age of his mother = 32 years

Step-by-step explanation:

given that,

the present ages of an arnav parents are in ratio 4 is to 5

let the common ratio of their ages be x

so,

present age of his father = 5x

present age of his mother = 4x

now,

given that,

8 years later the ratio of the ages change to 5 is 6

so,

According to the question,

(4x + 8)/(5x + 8) = 5/6

6(4x + 8) = 5(5x + 8)

24x + 48 = 25x + 40

25x - 24x = 48 - 40

x = 8

now,

age of his father = 5x

= 5(8)

= 40 years

age of his mother = 4x

= 4(8)

= 32 years

so,

Age of his father = 40 years

Age of his mother = 32 years

Answered by VishalSharma01
123

Answer:

Step-by-step explanation:

Given :-

The present ages of an arnav parents are in ratio 4 : 5

8 Years later, the ages were 5 : 6

To Find :-

The present ages.

Solution :-

Let the ages of the arnav's parents is x.

Arnav's father present age be = 5x

Arnav's mother present age be = 4x

Equating all the given values,

⇒ (4x + 8)/(5x + 8) = 5/6

⇒ 6(4x + 8) = 5(5x + 8)

⇒ 24x + 48 = 25x + 40

⇒ 25x - 24x = 48 - 40

⇒ x = 8

Present age of his father = 5x = 40 years

Present age of his mother = 4x = 32 years

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