Evaluate [
cos θ + sin θ √2 sin θ
− √2 sin θ cos θ − sin θ
]
n
Answers
Answered by
1
Answer:
Step-by-step explanation:
Correct option is A)
Given,
cosθ−sinθ=
2
sinθ
Squaring, we get
cos
2
θ+sin
2
θ−2sinθcosθ=2sin
2
θ
or 1−2sinθcosθ=2(1−cos
2
θ)
or 1+2sinθcosθ=2cos
2
θ
or sin
2
θ+cos
2
θ+2sinθcosθ=2cos
2
θ
or (sinθ+cosθ)
2
=2cos
2
θ
∴sinθ+cosθ=
2
cosθ
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