Math, asked by srishtijindal110, 5 days ago

Evaluate [

cos θ + sin θ √2 sin θ
− √2 sin θ cos θ − sin θ
]
n

Answers

Answered by ysatvik097
1

Answer:

Step-by-step explanation:

Correct option is A)

Given,  

cosθ−sinθ=  

2

sinθ

Squaring, we get

cos  

2

θ+sin  

2

θ−2sinθcosθ=2sin  

2

θ

or 1−2sinθcosθ=2(1−cos  

2

θ)

or 1+2sinθcosθ=2cos  

2

θ

or sin  

2

θ+cos  

2

θ+2sinθcosθ=2cos  

2

θ  

or (sinθ+cosθ)  

2

=2cos  

2

θ

∴sinθ+cosθ=  

2

cosθ

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