Evaluate cos²θ* tan²θ +
tan²θ* sin²θ in terms of tan θ.
Answers
Answered by
0
Answer:
tan square0 ( 1)
Step-by-step explanation:
tansquare0( sin square0 plus cos square0)
tan square0( 1)
Answered by
1
Step-by-step explanation:
cos²θ* tan²θ + tan²θ* sin²θ = tan²θ(cos²θ+sin²θ) [cos ²θ+sin²θ=1]
=tan²θ(1)
=tan²θ
Similar questions