Question

Evaluate:-
cos²60°tan²30°+sin30°cos0°sin60°tan45°

Answer 1

Answer:

Step-by-step explanation:

cos 60 = 1/2

cos [tex]cos^{2}[/60] = 1/4

tan 30 = 1/√3

tan[tex]tan^{2}[/30] = 1/3

sin 30 = 1/2

cos 0 = 1

sin 60 = √3/2

tan 45 = 1

THEREFORE ,

SOLVING WE GET

1/12 + √3/2  

HOPE U GET IT :D

Answer 2

$\textbf{\pink{\large{\underline{\underline{ANSWER:-}}}}}$

$\cos^2{60°}tan^2{30°}+sin30°cos0°sin60°tan45°\\={(\frac{1}{2})}^2\times{(\frac{1}{\sqrt3})}^2+\frac{1}{2}\times{1}\times{\frac{\sqrt3}{2}}\times{1}\\=\frac{1}{12}+\frac{1}{2}\times\frac{\sqrt3}{2}\\=\frac{1}{12}+\frac{\sqrt3}{4}\\=\frac{1+3\sqrt3}{12}$

$\textbf{\blue{\large{\underline{Hope it helps you}}}}$