Question

Evaluate cosec 0 sec (90° - 0) - cote tan (90°- 0) + sin? 32° + sin? 58°
tan 3 tan 22° tan 45º tan 68° tan 87° - tan- 32° + cosec 58°​

Answer 1

Step-by-step explanation:

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Answer 2

Answer:

2

2

Step-by-step explanation:

cosec0=sec (90-0)

cot0=tan (90-0)

sin 32=cos (90-32)=cos58

so

cosec 0 sec (90° - 0) - cote tan (90°- 0) + sin? 32° + sin? 58°

=cosec^2 0-cot^2 0+sin^2 32+cos^2 32

(cosec^2 -cot^2 =1

sin^2+cos^2=1)

=1+1=2

tan 3 = cot 87

tan 22 =cot 68

tan 45 = 1

tan 32 =cot 58

also

cosec^2 - cot^2 = 1

so

tan 3 tan 22° tan 45º tan 68° tan 87° - tan^2 32° + cosec^2 58

=cot87 tan87 cot 68. tan 68 *1 +1

=1+1 = 2

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