Question

Evaluate : cot 15°. cot 33°. Cot 45° . cot 57°. cot 75°- cos 0°
PLS TELL FAST

Answer 1

Answer:

the answer is 0 of this question

plzz mark as brainliest if it helps

Answer 2

Answer:

0

Step-by-step explanation:

Re-arranging the terms, we get,

= cot 15°.cot 75°.cot 57°.cot 33°.cot 45° - cos 0°

= cot(90°-75°).cot 75°. cot(90°-33°). cot 33° - cos 0°

= tan 75° . $\frac{1}{tan 75}$. tan 33°. $\frac{1}{tan 33}$. cot 45° - cos 0°(∵ cot(90° - θ) = tanθ & cotθ= 1/tanθ)

tan 75° and tan 33° will get cancelled and we will remain with 1.

So, plugging int he values of cot 45° and cos0°, we get,

1(1)-1 = 1-1 = 0

Please mark as Brainliest!

Thank you!